Instant Notes: Analytical Chemistry

(Tina Meador) #1
found within ± 1 sof the mean, approximately 95% will be found within ± 2 sand
approximately 99.7% within ± 3 s. More practically convenient levels, as shown
in Figure 3, are those corresponding to 90%, 95% and 99% of the population,
which are defined by ±1.64s, ±1.96sand ±2.58srespectively. Many statistical
tests are based on these probability levels.

The value of the population standard deviation, s, is given by the formula

s=



(1)

where xirepresents any individual value in the population and Nis the total
number of values, strictly infinite. The summation symbol, S, is used to show
that the numerator of the equation is the sum for i = 1 to i =Nof the squaresof
the deviationsof the individual xvalues from the population mean, m. For very
large sets of data (e.g., when N >50), it may be justifiable to use this formula as
the difference between sand swill then be negligible. However, most analytical
data consists of sets of values of less than ten and often as small as three.
Therefore, a modified formula is used to calculate an estimated standard
deviation, s, to replace s, and using an experimental mean, x

_
, to replace the
population mean, m:

s=



(2)




i=N

i= 1

(xi−x

_
)^2

N− 1




i=N

i= 1

(xi−m)^2

N

B2 – Assessment of accuracy and precision 29


–4s –3s –2s –1s 01 s 2 s 3 s 4 s

Relative
frequency (

y/

N

)

–1.29s +1.29s

80%

–4s–3s–2s–1s 01 s 2 s 3 s 4 s

Relative
frequency (

y/

N

)

–1.64s +1.64s

90%

–4s –3s –2s –1s 01 s 2 s 3 s 4 s

Relative
frequency (

y/

N

)

–1.96s +1.96s

95%

–4s–3s–2s–1s 01 s 2 s 3 s 4 s

Relative
frequency (

y/

N

)

–2.58s +2.58s

99%

Fig. 3. Proportions of a population within defined limits of the mean.

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