Chapter 16 : Virtual Work 347
From the geometry of the figure, we find that when the virtual upward displacement of thebeam at the hinge (i.e. C) is y, then virtual displacement of B and E is^7
9
y and^6
10y
=
3
5y
respectivelyas shown in Fig. 16.5.
∴ Total work done by the three reactions (RA, RB and RD)
7
[( 0) ( 0)]
9
AB Dy
RR R
⎛⎞
=+ × +⎜⎟× + ×
⎝⎠
7
B 9y
=+R × ...(i)
...(Plus sign due to reactions acting upwards)
and virtual work done by the load
3
–700 –420
5
y
=×=y ...(ii)
...(Minus sign due to load acting downwards)
We know that from the principle of virtual work, that algebraic sum of the total virtual
works done is zero. Therefore
7
–420 0
B 9
y
Ry×=or9
420 540 N
B 7
Ry
y=×= Ans.Example 16.3. Two beams AE and BD are supported on rollers at B and C as shown in
Fig. 16.6.
Fig. 16.6.
Determine the reactions at the rollers B and C, using the method of virtual work.
Solution. Given : Length of beam AE = 6 m; Length of beam BD = 8 m; Distance AC = 5 m;
Load at E = 500 N; and load at F = 1000 N
Fig. 16.7.
Let RC = Reaction at the roller C, and
RB = Reaction at the roller B.
First of all, let us consider the beam AE with roller support at C as shown in Fig. 16.7 (a).