∫dm=M()massofthebody
r
M
cm = ∫rdm1
.
Note: If an object has symmetric uniform mass
distribution about x axis then y coordinate of COM is
zero and vice-versaCentre of Mass of a Uniform Rod
Suppose a rod of mass M and length L is lying along the
x-axis with its one end at x = 0 and the other at x = L.
Mass per unit length of the rod = M/L
Hence, dm, (the mass of the element dx situated atx = x is)=M
L
dxe coordinates of the element PQ are (x, 0, 0).
erefore, x-coordinate of COM of the rod will be
xxdmdmxM
L
dxMLxdxL
L L
L
cm ==
==
∫
∫
∫
∫0 0
01
2
()
e y-coordinate of COM is y
ydm
cm dm
==∫
∫0
Similarly, zcm = 0
i.e., the coordinates of COM of the rod areL
2
,, 00.
^
Or it lies at the centre of the rod.
RIGID BODY
A rigid body is one whose geometric shape and size
remains unchanged under the action of any external
force. When a rigid body performs rotational motion,
the particles of the body move in circles. e centres
of these circles lie on a straight line called the axis of
rotation, which is xed and perpendicular to the planes
of circle.Torque and Angular Momentum
Torque is the turning eect of a force. If a force acting
on a object has a tendency to rotate the body about an
axis, the force is said to exert a torque on the body. It is
a vector quantity. In vector form,
Torque, τ=×
rF
In magnitude, W = r F sinq.
Here q is the angle between
rFand.
Torque has the same dimensions as that of work i.e.
[ML^2 T–2]. But work is a scalar quantity whereas torque
is a vector quantity.
By convention, anticlockwise moments are taken as
positive and clockwise moments are taken as negative.Special Cases(the rod will not rotate)Ifqt= 0°, then = 0O Paxis of rotationr F• (^) O P
If = 180°, then = 0
(the rod will not rotate)
qt
axis of rotationF
r
Ifq= 90°, thent=rF(maximum torque)O Paxis of rotation F q= 90°rNote : Same force acting at the same point can produce
either anticlockwise or clockwise torque depending
upon the location of the axis of rotation as shown in
the gure.A BAxis of rotationF
Anticlockwise torqueCAxis of rotationF
Clockwise torqueCA BWork Done by Torque
Work done, W = torque u angular displacement
= W × 'qPower, PdW
dtd
dt===τθ
τω
Angular momentum of a particle about a given axis is
the moment of linear momentum of the particle about
that axis. It is denoted by symbol
L.
Angular momentum
Lr=×p
In magnitude, L = rp sinq
where q is the angle between rpand.
Angular momentum is a vector quantity. Its SI unit is
kg m^2 s–1. Its dimensional formula is [ML^2 T–1].Relationship between Torque and Angular
Momentum
Rate of change of angular momentum of a body is equal
to the external torque acting upon the body.
τext=dL
dt