respect to the pass axis of P 1. A monochromatic
source S of unpolarised light of intensity I 0 is
kept in front of the polaroid sheet P 1 as shown
in the gure. Determine the intensities of light
as observed by the observers O 1 , O 2 and O 3 as
shown.
SOLUTIONS
- No, the speed of light in glass (i.e., v) depends upon
the colour of light (i.e., O).
As P = c/v, v
c
=
μ
, where c is the speed of light in a
vacuum.
According to Cauchy's formula.
P = a + b/O^2 , where a and b are constant and their values
depend upon the nature of the substance.
us, v c
ab
=
- /λ^2
As Or > Ov, vv < vr i,e., violet component of white light
travels slower than the red component.
- Because of total internal reections, the diver will
not see anything above water. Instead, he would see the
reection of something on the sides and/or bottom of
the pool. - Because of their smaller wavelength, microwaves
are not bent by objects of normal dimensions. So they
can be used to beam signal in a particular direction. - As^1111110
Ff 12 fFff
=+, =−= or F = f
(as f 1 = f and f 2 = –f )
- Only those waves can be polarised which are
transverse in nature. us, light waves, which are
transverse in nature, can be polarised whereas sound
waves, which are longitudinal cannot be polarised. - Given that focal length of convex lens, f 1 = + 25 cm and
focal length of concave lens, f 2 = –20 cm
Equivalent focal length,
1111
25
1
20
1
Ff 12 f 100
= +=+
−
=−
? F = –100 cm
Power of the combination, P
F
==
−
=−
11
1
1
()mm
D
e focal length of the combination= 1 m = 100 cm.
e system will be diverging in nature as the focal length
is negative.
- From mirror formula,^111
vfu
=−
Now for a concave mirror, f < 0 and for an object is
placed on the le side of the mirror, the object distance
u < 0
? 2 f < u < f or^1
2
11
fuf
>>
or −<−<−
1
2
11
fuf
or^11
2
1111
fffuff
−<−<−^ or
1
2
1
0
fv
<<
is implies that v < 0 so that image is formed on le.
Also the above inequality implies
2 f > v
or |2f | < |v| [' 2 f and v are negative]
i.e., the real image is formed beyond 2f.
- (a) Microwaves are used in radar. Because of their
small wavelengths, microwaves are not diracted or
bent by objects of normal dimensions. So these waves
can be used to beam signal in a particular direction.
(b) X-rays are used to photograph internal parts of a
body, X-rays have high penetrating power.
(c) Infrared rays are used for taking photographs of the
sky during night and foggy conditions. is is because
these radiations are readily absorbed by water molecules
present in most materials. Aer absorption they heat up
the materials and their surroundings. - (a) Gamma rays lie between 10–11 m-10–14 m.
ese rays are used in radiotherapy to treat certain
cancers and tumors.
(b) Infrared waves lie between 10–4 m-10–6 m. ese
waves are used in taking photographs during conditions
of fog, smoke etc as these waves are scattered less than
visible rays. - Fringe width, β=Dλ
d
When D and d are kept xed, β
β
λ
11 λ
=
or λ λβ
(^1) β
1 630 81
72
==×.
.
==^5103
72
708 75
.
. nm
11. (a) From Snell’s law, we have :
sin()
sin()
i
r
=μ
At A, i = 60°; P =^3
Now, sin()
sin()
r
i
=
μ