480 Answers to Odd-Numbered Exercises
- Taking the hint and using the fact that∇^2 φ=−λ^2 φ, the left-hand side
becomes
(
λ^2 k−λ^2 m
)∫∫
Rφkφmwhile the right-hand side is zero, because of the boundary condition.Section 5.5
1.λn=αn/a,whereαnis thenth zero of the Bessel functionJ 0 .Thesolutions
areφn(r)=J 0 (λnr)or any constant multiple thereof.- This is just the chain rule.
- Rolle’s theorem says that if a differentiable function is zero in two places,
its derivative is zero somewhere between. From Exercise 4 it is clear that
J 1 must be zero between consecutive zeros ofJ 0. Check Fig. 7 and Table 1. - Use the second formula of Exercise 6, after replacingμbyμ+1onboth
sides.
9.u(r)=T+(T 1 −T)I 0 (γr)/I 0 (γa).
Section 5.6
1.v( 0 ,t)/T 0 ∼= 1 .602 exp(− 5. 78 τ)− 1 .065 exp(− 30. 5 τ),whereτ=kt/a^2.3.v(r,t)=∑∞
n= 1anJ 0 (λnr)exp(−λ^2 nkt),λn=αn/a.UseEq.(13)andotherstofindan=T 0 J 1 (αn/ 2 )/αnJ^21 (αn).- Integration leads to the equality
∫a
0(
rφ′^2)′
dr+λ^2∫a0r^2(
φ^2)′
dr= 0.The first integral is evaluated directly. The second must be integrated by
parts.Section 5.7
- Use
1
r
d
dr(
rd
drJ 0 (λr))
=−λ^2 J 0 (λr).- The frequencies of vibration areλmnc=αmnc/a.Thefivelowestvaluesof
αmn, in order, have subscripts( 0 , 1 ),( 1 , 1 ),( 2 , 1 ),( 0 , 2 ),and( 3 , 1 ).See
Table 1 in Section 5.6.