418 CHAPTER 10 • CONFORMAL MAPPING
15. Find the image of the sector r > 0, 0 < IJ < i• under w = !:;:.
- Show that the function fi (z) in Equation (10-22) is analytic on the ray x < - 1,
y =O.
10.4 Mapping by Trigonometric Functions
The trigonometric functions can be expressed with compositions that involve
the exponential function followed by a bilinear function. We can find images
of certain regions by following the shapes of successive images in the composite
mapping.
• EXAMPLE 10.1 2 Show that the transformation w = tan z is a one-to-one
conformal mapping of the vertical strip lxl < i onto the unit disk lwl < 1.
Solution Using Equations (5- 32 ) and (5- 34 ) , we write
1 ei• - e -iz -iei2z + i
w =tanz= i eiz + e -iz = ei2z + 1 ·
Then, mapping w = t an z can be considered to be the composition
-iZ + i ·2
w = and Z = e' Z.
Z + l
The function Z = exp(i2z) maps the vertical strip lxl < i one-to-one and onto
the right half-plane Re ( Z) > 0. Then the bilinear transformation w = -~~ii
maps the half-plane one-to-one and onto the disk, as shown in Figure 10.16.
• EXAMPLE 10.13 Show that the transformation w = f (z) = sinz is a one-
to-one conformal mapping. of the vertical strip lxl < ~ onto the w plane slit
along the rays u::; -1, v = 0, and u :'.:: 1, v = O.
Solution Because f' ( z ) = cos z =f 0 for values of z sat isfying the inequality
2" < Re(z) < ~. it follows that w = sinz is a conformal mapping. Using
Equation (5-33), we write
u +iv= sin z = sinx coshy + icosxsinhy.
If lal < ~' then the image of the vertical line x =a is the curve in the w plane
given by the parametric equations