1550251515-Classical_Complex_Analysis__Gonzalez_

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266 Chapter5


  1. For w = (z^2 - 3z + 2)/(z^2 + 1), p = 2, so it has two zeros: 1, 2, and
    two poles: i, -i. The point oo is neither a zero nor a pole. In fact,
    w(oo) = 1.

  2. For a polynomial w = P(z)/1 = ao + alz + · · · + anzn (an ¥= 0), we
    have p = n. It has n zeros and n poles, namely, oo with multiplicity
    n. Note that in this case


Rl(z) = P ( ~) = ao + alz-
1
+ · · · + anz-n

aozn + alzn-l +···+an
=

which has z = 0 as a pole of order n.


Next, we wish to consider briefly a rational function of order 2 of the form

w=------ao + alz + a^2 z^2


b0 +biz+ b 2 z^2

(5.16-2)

where a2 ¥= O, b 2 ¥= O, and numerator and denominator have no common
factor of the form z - c. The condition for this to happen is that


By using bilinear transformations of both the dependent and indepen-
dent variables in (5.16-2), the function defined thereby can be reduced to
either of two simpler forms, depending on whether the function has a double
finite pole f3 or two distinct simple poles /3i, /32.

1. ·Suppose that b 0 +biz+ b 2 z^2 = b 2 (z - (3)^2 • Then (5.16-2) can be


written as

w=


Ao + Aiz + A2z^2
(z -(3)2

where Aj = aj/b 2 (j = 0, 1, 2). If we now let z = f3 + 1/(, we have


Ao+ Ai(/3 + 1/() + A 2 ((3 + 1/()^2

w = 1/(2

= Ao(^2 + Ai((/3( + 1) + A2(/3( + 1)^2
= B2(^2 +Bi(+ Bo
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