Sequences, Series, and Special Functions
since
I
1
( :: ~ ) I = 4lx^2 ~ y^2 I
and Ju-v = lx-yl
Finally,· letting u = v + t^2 in the last integral, we obtain
22z-1r(z)r(z + 1/2) = 2100 e-vv2z-1 dv loo e-t2 dt
621
= ..)7rr(2z) (8.20-18)
This formula is due to Legendre .and is called the duplication formula for
the r-function.
Although the formula has been established with the restriction Re z > 0,
by the identity principle for analytic functions the formula holds good for
all values of z for which both sides of the equation are defined, namely, for
all z E C - {O, -%, -1, -^3 / 2 , ••• }.
(11) Again, in view of the identity principle, to prove this property it
suffices to show that
{oo e-ttz-1 dt = lim n!nz
lo n->oo z(z + 1) · · · (z + n)
whenever Rez > 0. To do this, consider the function
r t n
g(n,z)= lo (1-;;:) tz-^1 dt
= nz 11 (1-rtrz-1 dr
where the second integral is obtained from the first by the substitution
t = nr. If Re z > 0, integration by parts gives
rl (1 -T )nrz-l dr = ~ r1 (1 -T r-lTz dr
lo z lo
= n(n - 1) · · ·^2 ·^1 1 Tz n dr
1
+ -1
z(z+l)···(z+n-l) 0
n!
= ~------
z ( z + 1) · · · ( z + n)
Hence
nlnz
g(n,z) = ----· ---
. z(z + 1) · · · (z + n)
and we must show that J 000 e-ttz-l dt = limn_, 00 g(n, z).