1550251515-Classical_Complex_Analysis__Gonzalez_

(jair2018) #1
Sequences, Series, and Special Functions

since

I
1
( :: ~ ) I = 4lx^2 ~ y^2 I
and Ju-v = lx-yl

Finally,· letting u = v + t^2 in the last integral, we obtain


22z-1r(z)r(z + 1/2) = 2100 e-vv2z-1 dv loo e-t2 dt


621

= ..)7rr(2z) (8.20-18)


This formula is due to Legendre .and is called the duplication formula for
the r-function.

Although the formula has been established with the restriction Re z > 0,

by the identity principle for analytic functions the formula holds good for
all values of z for which both sides of the equation are defined, namely, for

all z E C - {O, -%, -1, -^3 / 2 , ••• }.


(11) Again, in view of the identity principle, to prove this property it
suffices to show that

{oo e-ttz-1 dt = lim n!nz
lo n->oo z(z + 1) · · · (z + n)

whenever Rez > 0. To do this, consider the function

r t n
g(n,z)= lo (1-;;:) tz-^1 dt

= nz 11 (1-rtrz-1 dr


where the second integral is obtained from the first by the substitution


t = nr. If Re z > 0, integration by parts gives


rl (1 -T )nrz-l dr = ~ r1 (1 -T r-lTz dr


lo z lo

= n(n - 1) · · ·^2 ·^1 1 Tz n dr


1

+ -1

z(z+l)···(z+n-l) 0
n!
= ~------
z ( z + 1) · · · ( z + n)
Hence
nlnz
g(n,z) = ----· ---

. z(z + 1) · · · (z + n)


and we must show that J 000 e-ttz-l dt = limn_, 00 g(n, z).

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