676 Chapter9
tyt
a, rc;;f~ a2
/ /
/
QC~ /'
an c+
Fig. 9.6
which is equivalent to (9.9-1).
Remark In view of Theorem 7.13 (strong form of the Cauchy-Goursat
theorem) the hypothesis in Theorem 9.9 can be weakened by requiring only
continuity of f(z) on c+. We shall refer to this as the strong form of the
residue theorem.
Corollary 9.3 If f has a finite number of isolated singularities in CC*, then
the sum of the residues of f at the finite singularities plus the residue at
oo (which may or may not be singular) is zero.
Proof Let c+: z = Reit, 0:::; t:::; 2?T, be a circle about the origin with ra-
dius R large enough so as to contain in its interior all the finite singularities
ak off (k = l, .. .,n). By Definition 9.12 we have
~~f(z) = 2 ~i j f(z)dz
c-
Hence
- Res f(z) = -.^1 J J(z) dz='""" n Res f(z)
z=oo 2?Ti L..J z=ak
a+ k=I
according to (9.9-2). Thus it follows that
n
L Res f(z) +Res f(z) = 0
k=l z=ak z=oo
(9.9-3)
Note If all the finite singularities of f lie within the contour C, then
from (9.9-1) and (9.9-3) we obtain
j f(z)dz=-~?Ti~~f(i) (9.9-4)
c+