Mathematics Times – July 2019

(Ben Green) #1

11.Sol:


12.Sol:


the smallest possible integer value of c is 2.
11.Sol: Rewrite the given equation


cos 1 sin^7  ^4 
Since sin ( )^4 x positive in the given interval ,
so RHS is greater than one, that is
cos ( )^7   1. Using definition, we have
cos ( ) 1^7  . So the possible values of
cos 1 and sin 0. Therefore two
intersecting points , those are when  0 and
  2.
12.Sol: We can see from the given equation,
RHS- can factored. Thus
2 (3 2 3 2 ) 4 83m m n w n m  


implies that m 2 and
3 2 3 2 83^2   n w n^2
That is
2 3 2 74n w n^2
2 (4 3 1) 2 37n^2    w
implies that n- 2 = 1 i.e., n = 3 and
4 3 1 37  w
that is

(^) 3 9w
implies that w = 2. Therefore the value of the
expression m mn n^2  ^2 is
(^) 2 2 3 3 4 6 9 19^2       ^2

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