Barrons AP Calculus - David Bock
(B) The given limit is f ′(e), where f (x) = ln x. ...
(B) The given limit is the derivative of f (x) = cos x at x = 0; f ′(x) = − sin x. ...
(B) but f (1) = 4. Thus f is discontinuous at x = 1, so it cannot be differentiable. ...
(E) so the limit exists. Because g(3) = 9, g is continuous at x = 3. Since ...
(E) Since f ′(0) is not defined; f ′(x) must be defined on (−8,8). ...
(A) Note that f (0) = = 0 and that f ′(x) exists on the given interval. By the MVT, there is a number, c, in the interval such ...
(B) Since the inverse, h, of f (x) = is h(x) = then h ′(x) = Replace x by 3. ...
(D) After 50(!) applications of L’Hôpital’s Rule we get which “equals” ∞. A perfunctory examination of the limit, however, show ...
(C) cos(xy)(xy ′ + y) = 1; x cos(xy)y ′ = 1 − y cos(xy); ...
NOTE: In Questions 46–50 the limits are all indeterminate forms of the type We have therefore applied L’Hôpital’s Rule in each o ...
47. (C) [We rewrite As x → 0, so do 3x and 4x; the fraction approaches 1 · 1 · ] ...
48. (E) [We can replace 1 − cos x by getting ...
49. (D) [ as x (or πx) approaches 0, the original fraction approaches π · 1 · = π] ...
(C) The limit is easiest to obtain here if we rewrite: ...
(B) Since x − 3 = 2 sin t and y + 1 = 2 cos t, (x − 3)^2 + (y + 1)^2 = 4. This is the equation of a circle with center at (3,− ...
(C) Use L’Hôpital’s Rule; then ...
53. (A) ...
54. (D) ...
55. (E) ...
56. (C) Since ...
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