23.1. MIXTURESANDPURESTATES 359
andreflectsthefactthatthepurestateψ,unlikethemixture(23.2),isnotreally
inoneor theotherstateαz orβz. Ofcourse, theinterferencetermwill vanishif
αz andβzareeigenstatesofQ,e.g. ifQ=Sz. Otherwise,theinterferencetermis
notzero. Thus,allMaryhastodoisrunthebeamofelectronsemergingfromthe
firstdetectorintoaseconddetector,whichmeasureselectronspininthex-direction;
fromtheresulting
switchedoff.
Problem - For Q = Sx, calculate < Q >pure forthe purestate (23.1)with
A=−B= 1 /
√
2,andforthecorrespondingmixture.
Thefactthatmixturescanalwaysbedistinguishedfrompurestates, atleastin
principle,alsoholdsgoodforentangledpurestates. Consider,forexample,thepure
state
Ψ=
∑
i
ciφi(x 1 )φi(x 2 ) (23.6)
andthemixture
M={particleinoneofthestates φi(x 1 )φi(x 2 ) withprobability |ci|^2 } (23.7)
Suppose,forsimplicity,thatallthesestatesareorthonormal,i.e.
<φi|φj>=<φi|φj>=δij (23.8)
andthatAisanobservableofparticle1,andBanobservableofparticle2.Itiseasy
toseethatifwemeasureonlyA,oronlyB,thatthemixtureM andthepurestate
Ψgiveexactlythesameanswer,namely
<A> =
∑
i
|ci|^2 <φi|A|φi>
<B> =
∑
i
|ci|^2 <φi|B|φi> (23.9)
However,ifwemeasuretheexpectationvalueoftheproductAB,thenwefindthat
thepurestatepredicts
<AB>pure=
∑
ij
c∗icj<ψi|A|ψj><φi|B|φj> (23.10)
whileforthemixture
<AB>mix=
∑
i
|ci|^2 <ψi|A|ψi><φi|B|φi> (23.11)