y=f(0°)
=acos 0 °+q
=a(1) +q
=a+q
This gives the point(0°;a+q).
Worked example 19: Sketching a cosine graph
QUESTION
Sketch the graph off() = 2cos+ 3for 2 [0°; 360°].
SOLUTION
Step 1: Examine the standard form of the equation
From the equation we see thata > 1 so the graph is stretched vertically. We also see thatq > 0 so the graph is
shifted vertically upwards by 3 units.
Step 2: Substitute values for
0 ° 30 ° 60 ° 90 ° 120 ° 150 ° 180 ° 210 ° 240 ° 270 ° 300 ° 330 ° 360 °
f() 5 4,73 4 3 2 1,27 1 1,27 2 3 4 4,73 5
Step 3: Plot the points and join with a smooth curve
30 ◦ 60 ◦ 90 ◦ 120 ◦ 150 ◦ 180 ◦ 210 ◦ 220 ◦ 270 ◦ 300 ◦ 330 ◦ 360 ◦
1
2
3
4
5
f() = 2cos+ 3
f()
Domain:[0°; 360°]Range:[1; 5]
x-intercepts: noney-intercept:(0°; 5)
Maximum turning points:(0°; 5),(360°; 5)Minimum turning point:(180°; 1)
Chapter 6. Functions 195