7.2 CHAPTER 7. SOLVINGQUADRATIC EQUATIONS
(2b + 3)(b− 1) = 0
2 b + 3 = 0 or b− 1 = 0
b =
− 3
2
or b = 1
Step 5 : Check solutions in original equation
Both solutions are valid
Therefore, b =− 23 or b = 1
Exercise 7 - 1
Solve the following quadratic equations by factorisation. Some answers may be left in surd form.
- 2 y^2 − 61 = 101
- 2 y^2 − 10 = 0
- y^2 − 4 = 10
- 2 y^2 − 8 = 28
- 7 y^2 = 28
- y^2 + 28 = 100
- 7 y^2 + 14y = 0
- 12 y^2 + 24y + 12 = 0
- 16 y^2 − 400 = 0
- y^2 − 5 y + 6 = 0
- y^2 + 5y− 36 = 0
- y^2 + 2y = 8
13.−y^2 − 11 y− 24 = 0
- 13 y− 42 = y^2
- y^2 + 9y + 14 = 0
- y^2 − 5 ky + 4k^2 = 0
- y(2y + 1) = 15
- y^5 −y 2 +y^3 + 2 =y 2 −−^62 y
- yy−+1^2 =^2 yy−+1 7
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(1.) 0185 (2.) 0186 (3.) 0187 (4.) 0188 (5.) 0189 (6.) 018a
(7.) 018b (8.) 018c (9.) 018d (10.) 018e (11.) 018f (12.) 018g
(13.) 018h (14.) 018i (15.) 018j (16.) 018k (17.) 018m (18.) 018n
(19.) 018p