120 algebra De mystif ieD
DeMYSTiFieD / algebra DeMYSTiFieD / HuttenMuller / 000-0 / Chapter 5✔SOLUTIONS
1.^3
5
3
55
535
535(^25)
=⋅==
2.^77772
yy
y
yy
yy
y=⋅==3.^6
7
6
77
742
742(^27)
=⋅==
4.^8
3
8
33
383
383(^23)
xx=⋅==xx
5.^7
11
7
1111
1177
1177(^211)
xy=⋅xy ==xy xy
6.^2
10
2
1010
10210
10210
yy^210y
yy
yy
y=⋅==
()In the case of a cube (or higher) root, multiplying the fraction by the denom-
inator over itself usually does not work. To eliminate the nth root in the
denominator, we need to write the denominator as the nth root of some quan-
tity to the nth power. For example, to simplify^1(^35)
we need 5^3 under the radical.
To get 53 under the radical, we multiply the numerator and denominator by^352
over itself. Thus,
1
5
5
5
5
5
25
(^35)
3 2
3 2
3 2
3 3
3
⋅==
When the denominator is written as a power (often the power is 1) subtract
this power from the root. The factor will include this number as an exponent.
EXAMPLES
Rationalize the denominator.
(^483)
x
EXAMPLES
Rationalize the denominator.
EXAMPLES
Rationalize the denominator.