Chapter 8 linear appliCaTionS 255- Let x represent Ava’s final exam grade. Her test average is (68 + 73 + 80
- 95)/4 = 79. Then^13 test average + 31 presentation grade + 31 final exam
grade is 80 becomes
- 95)/4 = 79. Then^13 test average + 31 presentation grade + 31 final exam
1
379 1
375 1
38079
325
380379
325
3()++() ()=.++= ++
xx x
=
++⋅=++=380379
33253
324079 75 240()() xx
1154 240
154 154
86+=
−−
=xxAva’s final exam grade needs to be 86 to obtain an average of 80.
- Let x = sixth quiz grade. The course grade^45 quiz grade +^15 book report
becomes
4
5
72 66 69 80 85
61
5 +++++ 90
x + ().Simplified, the above is
4
5
372
618 4372 4
3018 1488 4
30 + 18
xx+=()+ += + x+.We want this quantity to equal 80.
1488 4
3018 80301488 4
3018 30 8030148+ += + +
=xx ()884
30 + 30 18 2400
x +=()