5 Steps to a 5 AP Calculus BC 2019

Applications of Derivatives 173

Step 2: Enter:y 1 =

√

((x−1)∧ 2 +x∧6).

Use the [Minimum] function of

the calculator and obtain

x=.65052 andy 1 =.44488.

Verify the result with the First

Derivative Test. Enter

y 2 =d(y1(x),x) and use the

[Zero] function and obtain

x=.65052.

0 0.65052

z′ –+ 0

z decr

rel min

incr

Thus, the shortest distance is

approximately 0.445.