5 Steps to a 5 AP Calculus BC 2019

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More Applications of Definite Integrals 313

13.2 Distance Traveled Problems


Summary of Formulas
Position Function:s(t);s(t)=


v(t)dt.

Velocity:v(t)=
ds
dt
;v(t)=


a(t)dt.

Acceleration:a(t)=
dv
dt

.


Speed:|v(t)|.
Displacement fromt 1 tot 2 =

∫t 2

t 1

v(t)dt=s(t 2 )−s(t 1 ).

Total Distance Traveled fromt 1 tot 2 =

∫t 2

t 1

∣∣
v(t)

∣∣
dt.

Example 1
See Figure 13.2-1.

0

10

–10

20

2 4 6 8 10 12

v(t)

v(t)

t
(seconds)

(feet/sec)

Figure 13.2-1

The graph of the velocity function of a moving particle is shown in Figure 13.2-1.
What is the total distance traveled by the particle during 0≤t≤12?

Total Distance Traveled=

∣∣


∫ 4

0

v(t)dt

∣∣

∣+

∫ 12

4

v(t)dt

=


1


2


(4)(10)+


1


2


(8)(20)= 20 + 80 =100 feet.

Example 2
The velocity function of a moving particle on a coordinate line isv(t)=t^2 + 3 t− 10
for 0 ≤ t ≤ 6. Find (a) the displacement by the particle during 0 ≤ t ≤ 6, and
(b) the total distance traveled during 0≤t≤6.
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