5 Steps to a 5 AP Calculus BC 2019

(Marvins-Underground-K-12) #1
Series 347

14.1 Sequences and Series


Main Concepts:Sequences and Series, Convergence

A sequence is a function whose domain is the non-negative integers. It can be expressed as a
list of terms{an}={a 1 ,a 2 ,a 3 ,...,an,...}or by a formula that defines thenth term of the
sequence for any value ofn. A series


an=

∑∞
n= 1

an=a 1 +a 2 +a 3 +···+an+···is the sum of
the terms of a sequence{an}. Associated with each series is a sequence of partial sums,{sn},
wheres 1 =a 1 ,s 2 =a 1 +a 2 ,s 3 =a 1 +a 2 +a 3 , and in general,sn=a 1 +a 2 +a 3 +···+an.

Example 1
Find the first three partial sums of the series
∑∞
n= 1

(−2)n
n^3

.


Step 1: Generate the first three terms of the sequence

{
(−2)n
n^3

}
.

a 1 =

(−2)^1


13


=−2,a 2 =

(−2)^2


23


=


4


8


=


1


2


,a 3 =

(−2)^3


33


=


− 8


27


Step 2: Find the partial sums.
s 1 =a 1 =−2,s 2 =a 1 +a 2 =− 2 +

1


2


=


− 3


2


,


s 3 =a 1 +a 2 +a 3 =− 2 +

1


2


+


− 8


27


=


− 97


54


≈− 1. 796


Example 2
Find the fifth partial sum of the series

∑∞
n= 1

5 +n^2
n+ 3

.


Step 1: Generate the first five terms of the sequence

{
5 +n^2
n+ 3

}
.

a 1 =

5 + 12


1 + 3


=


6


4


=


3


2


a 2 =

5 + 22


2 + 3


=


9


5


a 3 =

5 + 32


3 + 3


=


14


6


=


7


3


a 4 =

5 + 42


4 + 3


=


21


7


= 3 a 5 =

5 + 52


5 + 3


=


30


8


=


15


4


Step 2: The fifth partial sum isa 1 +a 2 +a 3 +a 4 +a 5 =

3


2


+


9


5


+


7


3


+ 3 +


15


4


=


743


60


.


Convergence
The series

anconverges if the sequence of associated partial sums,{sn}, converges. The
limit limn→∞sn=S, whereSis a real number, and is the sum of series,

∑∞
n= 1

an=S.If

∑∞
n= 1

anand
∑∞
n= 1

bnare convergent, then

∑∞
n= 1

can=c

∑∞
n= 1

anand

∑∞
n= 1

(an±bn)=

∑∞
n= 1

an±

∑∞
n= 1

bn.
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