Cracking The Ap Calculus ab Exam 2018

We can find the volume by taking a vertical slice of the region. The formula for the volume of a solid of re ...

The integral can be rewritten as − du Evaluating the integral, we get This can be simplified to Finally, subst ...

Now if we substitute x = 2, we get = 4 + 2 + Solving for y, we get y = ± A In order to find the ...

Y 2 = nDeriv(Y 1 ,X,X) Y 3 = nDeriv(Y 2 ,X,X) Graph Y 3 and find its zero. Make sure that only ...

You can’t evaluate this integral using any of the techniques that you have studied so far, so use the ...

Solving for , we get 4 + 6 = 0 and = − For y = 1 and x = −2, we get 2(−2)(1) + (−2)^2 + ...

(−0.786, 4.209). Graphing Calculator (TI-83 and TI-84) Press the Y= button, and enter the following values to the ...

We can find the volume by taking a vertical slice of the region. The formula for the volume of a solid of re ...

Let u = ln x. Then du = . Substituting, we get u du Now, we can evaluate the integral: + C. Subs ...

A We can evaluate this integral using u-substitution. Let u = sin(πx) and du = πcos(πx)dx so du = c ...

This gives us V = 8ekt Next, we use the condition that V = 12 at time t = 5 to solve for k. 1 ...

we need to find the derivative: = tan x + xsec^2 x. We plug in x = 1 to get the slope of the ...

ANSWERS AND EXPLANATIONS TO SECTION II The temperature on New Year’s Day in Hinterland was given by T(H) = −A ...

[a, b], with n trapezoids, is [y 0 + 2y 1 + 2y 2 + 2y 3 + ... + 2yn−1 + yn] Using the rule ...

This gives us G = 100ekt. Next, we use the condition that G = 120 at time t = 1 to solve for ...

G − = Cekt Solving for G, we get G = ekt + Now, set G = 0. We get 0 = ekt + Now, s ...

It is = 4x^3 + 12x^2 and, at x = −1, = 4(−1)^3 + 12(−1)^2 = 8. Now, we have the s ...

y = (−3)^4 + 4(−3)^3 = 81 − 108 = −27 Thus, the curve has an absolute minimum at (−3, −27). (c) Fi ...

water is 2 inches deep. First, rewrite the equation as V = πRh^2 − h^3 Now, take the derivative of th ...

(c) How fast is the circular area of the surface of the spherical segment of water growing (in in.^2 /sec) when ...