Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
15.

Use  the     Power   Rule    to  take    the     derivative  of  each    term.   The     derivative  of 

(remember   the shortcut    that    we  showed  you on  this    page).  The derivative  of      =   0   (because

the derivative  of  a   constant    is  zero).  Therefore,  the derivative  is  .

16. 0

The derivative  of  a   constant    is  zero.


  1. 3 x^2 + 6x + 3


First,  expand  (x  +   1)^3    to  get x^3     +   3x^2    +   3x  +   1.  Now,    use the Power   Rule    to  take    the derivative
of each term. The derivative of x^3 = 3x^2 . The derivative of 3x^2 = 3(2x) = 6x. The derivative of
3 x = 3. The derivative of 1 = 0 (because the derivative of a constant is zero). Therefore, the
derivative is 3x^2 + 6x + 3.

18.

Use  the     Power   Rule    to  take    the     derivative  of  each    term.   The     derivative  of 

(remember   the shortcut    that    we  showed  you on  this    page).  Rewrite     as  x   and     as  x.

The  derivative  of x    =   x .     The     derivative  of x    =   x .     Therefore,  the     derivative  is 

= .


  1. 6 x^2 + 6x − 14


First,  expand  x(2x    +   7)(x    −   2)  to  get x(2x^2  +   3x  −   14) =   2x^3    +   3x^2    −   14x.    Now,    use the Power
Rule to take the derivative of each term. The derivative of 2x^3 = 2(3x^2 ) = 6x^2 . The derivative
of 3x^2 = 3(2x) = 6x. The derivative of 14x = 14. Therefore, the derivative is 6x^2 + 6x − 14.

20.

First,  rewrite the terms   as   .  Next,   distribute  to  get:    .
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