Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Next,    we  need    to  find    where   the     two     curves  intersect,  which   will    be  the     endpoints   of  the

region. We  do  this    by  setting the two curves  equal   to  each    other.  We  get x^2     −   4x  −   5   =   2x  −   5.

The solutions   are (0, −5) and (6, 7). Therefore,  in  order   to  find    the area    of  the region, we  need

to  evaluate    the integral.    [(2x   −   5)  −   (x^2    −   4x  −   5)] dx  =       (−x^2   +   6x) dx. We  get     (−x^2   +

6 x)    dx  =       =       −   0   =   36.

4.

We  find    the area    of  a   region  bounded by  f(x)    above   and g(x)    below   at  all points  of  the interval

[a, b]  using   the formula  [f(x)  −   g(x)]   dx.

First,  let’s   make    a   sketch  of  the region.
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