Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Next,    we  need    to  find    where   the     two     curves  intersect,  which   will    be  the     endpoints   of  the

region. We  do  this    by  setting the two curves  equal   to  each    other.  We  get 4x  −   x^2     =   x^2 .   The

solutions   are (0, 0)  and (2, 4). Therefore,  in  order   to  find    the area    of  the region, we  need    to

evaluate     the     integral.      ((4x     −  x^2 ))  dx   =      (4x  −   2x^2 ) dx.  We  get     (4x     −   2x^2 ) dx   =  

= − 0 = .

3. 36

We  find    the area    of  a   region  bounded by  f(x)    above   and g(x)    below   at  all points  of  the interval

[a, b]  using   the formula  [f(x)  −   g(x)]   dx. Here    f(x)    =   2x  −   5   and g(x)    =   x^2     −   4x  −   5.

First,  let’s   make    a   sketch  of  the region.
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