Math Word Problems Demystified - A Self Teaching Guide

(Marvins-Underground-K-12) #1

EXAMPLE:Change each fraction or mixed number to a percent:


(a)

3

5

(b)

9

10

(c)

5

8

(d) 1

1

4

SOLUTION:

ðaÞ 5 Þ 3 : 0

: (^63)
5


¼ 0 : 6 ¼ 60 %

30

0

ðbÞ 10 Þ 9 : 0

: (^99)
10


¼ 0 : 9 ¼ 90 %

90

0

ðcÞ 8 Þ 5 : 00

: (^6255)
8


¼ 0 : 625 ¼ 62 : 5 %

48

20

16

40

40

0

ðdÞ 1

1

4

¼

5

4

4 Þ 5 : 00

1 : 25

1

1

4

¼ 1 : 25 ¼ 125 %

4

10

8

20

20

A percent word problem has three numbers: the whole, total, or base (B);
the part (P); and the rate or percent (R). Suppose that in a class of 30
students, there are 6 absent. Now the whole or total is 30 and the part is 6.
The rate or percent of students who were absent is 306 ¼^15 ¼ 20 %.
In a percent problem, you will be given two of the three numbers and will
be asked to find the third number. Percent problems can be solved by using a
percent circle. The circle is shown in Figure RIII-1.


REFRESHER III Percents 37

Free download pdf