AP Physics C 2017
The Drill In the diagrams below, assume all pulleys and ropes are massless, and use the following variable defini ...
7 . Frictionless 8 . Frictionless 9 . Frictionless 10 . Coefficie ...
11 . Coefficient of Friction μ 12 . Frictionless 13 . Frictionless 14 . ...
The Answers (Step-by-Step Solutions to #2 and #5 Are on the Next Page.) 1 . a = 10 m/s^2 2 . a = 3.3 m/s^2 T ...
12 . a = 5.0 m/s^2 T = 15 N 13 . a = 3.3 m/s^2 T 1 = 13 N T 2 = 20 N 14 . a = 0.22 m/s^2 T 1 = ...
No components are necessary, so on to Step 3 : write Newton’s second law for each block, calling clockwise ...
The electric field above has magnitude 3.0 N/C. For each of the following particles placed in the field, f ...
a = 2.8 × 10^8 m/s^2 , right. 12 . F = 4.8 × 10−19 N, right. a = 5.3 × 10^11 m/s^2 , right. 13 . F = 4.8 ...
F = (1.6 × 10−19 C)(3 N/C) = 4.8 × 10−19 N Because the electron has a negative charge, the force is op ...
3 . 4 . 5 . 6 . 7 . ...
8 . Careful—this one’s tricky. The Answers (A Step-by-Step Solution to #1 Is on the Next Page.) 1 . a = ...
a = 1.5 m/s^2 , down the plane. t = 5.2 s to reach bottom. So, a total of t = 5.6 s for the block to go u ...
To find the time, plug into a kinematics chart: Solve for t using the second star equation for kinematic ...
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The Answers Note that our descriptions of the moving objects reflect our own imaginations. You might have come ...
4 . The steady speed over 200 s (a bit over 3 minutes) is 0.25 m/s, or 25 cm/s, or ...
experiment is dropped from a 250-ft tower, hitting the ground with a speed close to 90 mph. 11 . 1 cm/s ...
4 . 5 . 6 . 7 . ...
The Answers (A Step-by-Step Solution to #2 Is on the Next Page.) 1 . 2 . (Remember, a kΩ is 1000 Ω ...
6 . 7 . Step-by-Step Solution to #2: Start by simplifying the combinations of resistors. The 8 kΩ and 1 ...
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