CK-12 Geometry-Concepts

(Marvins-Underground-K-12) #1

11.5. Pyramids http://www.ck12.org



  1. In this example, we are given the slant height. For volume, we need the height, so we need to use the Pythagorean
    Theorem to find it.


72 +h^2 = 252
h^2 = 576
h= 24

Using the height, the volume is^13 ( 142 )( 24 ) = 1568 units^3.



  1. The base of this pyramid is a right triangle. So, the area of the base is^12 ( 14 )( 8 ) = 56 units^2.


V=


1


3


( 56 )( 17 )≈ 317. 33 units^3


  1. The formula for the volume of a pyramid works for any pyramid, as long as you can find the area of the base.


224 = 56 h
4 =h

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Fill in the blanks about the diagram below.


1.xis the ___________.


  1. The slant height is ____.
    3.yis the ___.

  2. The height is ____.

  3. The base is ___.

  4. The base edge is ____.


Find the area of a lateral face and the volume of the regular pyramid. Leave your answer in simplest radical form.

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