CK-12 Geometry-Concepts

(Marvins-Underground-K-12) #1

http://www.ck12.org Chapter 11. Surface Area and Volume



  1. Find the volume of the pyramid.

  2. A rectangular pyramid has a base area of 56cm^2 and a volume of 224cm^3. What is the height of the pyramid?


Answers:



  1. The area of the base isA=^14 s^2



3 because it is an equilateral triangle.

B=


1


4


82



3 = 16



3


SA= 16



3 +


1


2


( 24 )( 18 ) = 16



3 + 216 ≈ 243. 71



  1. In the formula for surface area, the lateral surface area is^12 Plor^12 nbl. We know thatn=4 andb=l. Let’s solve
    forb.


1


2


nbl= 72 f t^2
1
2

( 4 )b^2 = 72
2 b^2 = 72
b^2 = 36
b= 6

Therefore, the base edges are all 6 units and the slant height is also 6 units.



  1. To find the area of the base, we need to find the apothem. If the base edges are 10 units, then the apothem is 5



3


for a regular hexagon. The area of the base is^12 asn=^12


(


5



3


)


( 10 )( 6 ) = 150




  1. The total surface area is:


SA= 150



3 +


1


2


( 6 )( 10 )( 22 )


= 150



3 + 660 ≈ 919. 81 units^2
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