AP Biology Practice Exam 1 ❮ 279
PART B: GRID-IN QUESTIONS
- 4.26—If the green-melon parents were Gg, you
would expect a cross with a yellow-melon plant
(gg) to produce 50 percent Gg and 50 percent gg
offspring. What you actually observed was
53 green and 41 yellow. Based on a total number
of 94 offspring, your expected half-and-half
ratios would be 47 of each color.
# OBSERVED (o) # EXPECTED (e) (o -e) (o -e)^2 (o-e)^2 /e
green-melon plant 53 47 6 36 0.766
yellow-melon plant 41 47 –6 36 0.766
The chi-square value is 1.53 (less than the criti-
cal value of 3.84), so the null hypothesis is
accepted.
2. 0.52
tan=p; green =q
green phenotype =q^2 =0.23; frequency of green
allele=√0.23=0.48
Sincep+q=1, the tan allele (p)= 1 −0.48=
− / / / 0.52.
1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0
624
1 2 3 4 5 6 7 8 9
− / / /
1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0 1 2 3 4 5 6 7 8 9
0
25
1 2 3 4 5 6 7 8 9
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