AP Statistics 2017

used for the study. Assuming that the population from which the sample is drawn is approximately normal, wh ...

Construct a 99% confidence interval for the true difference between the mean score for males and the mean ...

the true mean differs from 190 hours. Do not actually carry out the complete test, but do state the null ...

The correct answer is (e). P = 0.7, M = 0.05, z * = 1.96 (for C = 0.95) . You need a sample ...

Free-Response C = 0.90 z * = 1.645, . You would need to survey at least 271 students. The popu ...

Since we do not know σ , but do have a large sample size, we will use a t procedure. , df ...

9. The conditions are present to construct a one-proportion z interval. We are 95% confident that the true propo ...

If the true mean is really 38, we are almost certain to reject the false null hypothesis. For a given ...

Since we do not know σ, however, a t interval is more appropriate. The TI-83/84 calculator returns a t ...

(a) It is an observational study because the researchers are simply observing the results between t ...

CHAPTER 11 Confidence Intervals and Introduction to Inference A recent poll estimated that about 18% ...

(E) Why is t used instead of z as the critical value in a confidence interval for a mean? (A) Beca ...

CHAPTER 12 Inference for Means and Proportions IN THIS CHAPTER Summary: In the last chapter, we concentrated ...

Significance Testing Before we actually work our way through inference for means and proportions, we need ...

III. Do the correct mechanics, including calculating the value of the test statistic and the P -val ...

data could plausibly have come from an approximately normal population. A stemplot, boxplot, dotplot, ...

example: A study was done to determine if 12- to 15-year-old girls who want to be engineers differ in IQ fr ...

want to be engineers differs from the mean IQ of all girls in this age range. Notes on the above solut ...

evidence that the true mean IQ for girls who want to be engineers differs from the mean IQ of all g ...

III . = 1.75, s = 2.49, , df = 8 – 1 = 7. 0.025 < P < 0.05 (from Table A). Using the ...