96 CHAPTER 2 Linear Equations and Inequalities in One Variable
Complete solution available
on the Video Resources on DVD
2.2 EXERCISES
1.Concept Check Tell whether you would use the addition or multiplication property of
equality to solve each equation. Do not actually solve.
(a) (b) (c) (d)
2.Concept Check Which equation does notrequire the use of the multiplication property
of equality?
A. B. C. D.
3.How would you find the solution of a linear equation with next-to-last step “ ?”
4.In the statement of the multiplication property of equality in this section, there is a
restriction that. What would happen if you multiplied each side of an equation by 0?
Concept Check By what number is it necessary to multiply both sides of each equation to
isolate x on the left side? Do not actually solve.
9. 10. 11. 12.
Concept Check By what number is it necessary to divide both sides of each equation to iso-
late x on the left side? Do not actually solve.
Solve each equation, and check your solution. See Examples 1–6.
41. 42. 43. 44.
45. 46. 47. 48.
49. 50. 51. 52.
53. 54. 55. 56.
Solve each equation, and check your solution. See Example 7.
- 7 m+ 6 m- 4 m= 63 64. 9 r+ 2 r- 7 r= 68 65.- 6 x+ 4 x- 7 x= 0
2
3
x-
5
9
x= 4
2
5
x-
3
10
3 p- 7 p= 24 x= 2
4 x+ 3 x= 21 8 x+ 3 x= 121 6 r- 8 r= 10
- 0.3x= 9 - 0.5x= 20
5
6
x=
4
9
-
7
9
x=
3
5
-
3
4
- z=- 21
5
6
t=- 15
3
8
x= 9
2
7
p= 4
r
8
=- 3
x
7
=- 5
x
5
= 15
z
6
= 12
1
5
p=- 3
1
4
- 2.1m=25.62 -3.9x=32.76 x=- 12
- x=- 0.2t= 8 0.9x= 18
1
2
- x=-
3
4
4 r= 0 7 x= 0 - x= 12 - t= 14
10 t=- 36 10 s=- 54 - 6 x=- 72 - 4 x=- 64
4 x=- 20 5 x=- 60 - 7 x= 28 - 9 x= 36
6 x= 36 8 x= 64 2 m= 15 3 m= 10
0.12x= 48 0.21x= 63 - x= 25 - x= 50
6 x= 5 7 x= 10 - 4 x= 16 - 13 x= 26
- x=0.75 -x=0.48
8
3
- x=- 11
9
2
x=- 4
x
100
= 10
x
10
= 5
2
3
x= 6
4
5
x= 8
CZ 0
- x= 5
x
3
- 5 x- 4 x= 7 =- 2
1
4
3 x- 5 x= 6 x= 12
3 x= 12 3 +x= 12 - x= 4 - 12 = 6 +x
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