124 3 Real Analysis
375.Leta 0 =1994 andan+ 1 = a
n^2
an+ 1 for each nonnegative integern. Prove that for
0 ≤n≤998, the number 1994−nis the greatest integer less than or equal toan.
376.Fixka positive integer and define the sequence
an=
⌊
(k+
√
k^2 + 1 )n+
(
1
2
)n⌋
,n≥ 0.
Prove that
∑∞
n= 1
1
an− 1 an+ 1
=
1
8 k^2
.
The telescopic method can be applied to products as well. Within the first, relatively
easy, problem, the reader will recognize in disguise the Fermat numbers 2^2
n
+1,n≥1.
Example.Define the sequence(an)nbya 0 =3, andan+ 1 =a 0 a 1 ···an+2,n≥0.
Prove that
an+ 1 = 2 (a 0 − 1 )(a 1 − 1 )···(an− 1 )+ 1 , for alln≥ 0.
Solution.The recurrence relation givesa 0 a 1 ···ak− 1 =ak−2,k≥1. Substitute this
in the formula forak+ 1 to obtainak+ 1 =(ak− 2 )ak+2, which can be written as
ak+ 1 − 1 =(ak− 1 )^2. And so
ak+ 1 − 1
ak− 1
=ak− 1.
Multiplying these relations fork= 0 , 1 ,...,n, we obtain
an+ 1 − 1
an− 1
·
an− 1
an− 1 − 1
···
a 1 − 1
a 0 − 1
=(an− 1 )(an− 1 − 1 )···(a 0 − 1 ).
Since the left-hand side telescopes, we obtain
an+ 1 − 1
a 0 − 1
=(a 0 − 1 )(a 1 − 1 )···(an− 1 ),
and the identity follows.
A more difficult problem is the following.
Example.Compute the product
∏∞
n= 1
(
1 +
(− 1 )n
Fn^2
)
,
whereFnis thenth Fibonacci number.