P1^
6
The reverse chain rule
EXAMPLE 6.15 Find the area between the curve y = x and the y axis between y = 0 and y = 3.SOLUTIONA = (^) ∫
3
0 x^ dy
= (^) ∫
3
0 y
(^2) dy
=
y^3
03
3
= 9 square units.EXERCISE 6E Find the area of the region bounded by each of these curves, the y axis and the
lines y = a and y = b.
1 y = 3 x + 1, a = 1, b = 7. 2 y = x–, 2 a = 0, b = 2.3 y =^3 x, a = 0, b = 2. 4 y = x − 1, a = 0, b = 2.
5 y = 4 x, a = 1, b = 2. 6 y = 3 x − 2, a = −1, b = 1. The reverse chain rule
ACTIVITY 6.3 (i) Use the chain rule to differentiate these.
(a) (x − 2)^4 (b) (2x + 5)^7(c)1
() 21 x−^3 (d) () 18 − xSince y = x, x = y^2
yx3Oy = xFigure 6.22yx71Oy = 3x + 1yx2Oy = x – 2You can think of the chain rule
as being: ‘the derivative of the
bracket × the derivative of the
inside of the bracket’.