Solution by the method of elimination :
Conveniently, one equation or both equations are multiplied by such a number so
that after multiplication, absolute value of the coefficients of the same variable
become equal. Then as per need, if the equations are added or subtracted, the
variable with equal coefficient will be eliminated. Then, solving the obtained
equation, the value of the existing variable will be found. If that value is put
conveniently in any of the given equations, value of the other variable will be found.
(3) Method of cross-multiplication :
We consider the following two equations :
..........( )...........()
0 20 1
2 2 21 1 1
ax by cax by cMultiplying equation (1) by b 2 and equation (2) by b 1 , we get,
.........( ).........()
0 40 3
21 12 1212 12 21
abx bby bcabx bby bcSubtracting equation (4) from equation (3), we get
..........( 5 )1
or,or,( )( ) 012 21 12 2112 21 12 2112 21 21 12bc bc ab abxab ab x bc bcab ab x bc bc
Again, multiplying equation (1) by a 2 and equation (2) by a 1 , we get,
.........().........()
0 70 6
1 2 12 211 2 21 12
aax aby caaax aby caSubtracting equation (7) from equation (6), we get
..........( 8 )1
or,or, ( ) ( )( ) 01 2 2 1 12 2112 21 12 2121 12 1 2 2 1ca ca ab abyab ab y ca caab ab y ca ca
From (5) and (8) we get,
12 21 12 21 12 211
ca ca ab aby
bc bcx
From such relation between xand y, the technique of finding their values is called
the method of cross-multiplication.
From the above relation between xandy, we get,