Growing Elite Marijuana

(Ron) #1

2.5 feet wide and 8.5 feet high contains
127.5 ft^3. Then they multiply that number
by .0015. In this case the figures look like
this: 127.5 x .0015 = 191 ft^3.
One grower had a closet 3 feet by 3
feet by 10 feet. He figured that its area was
90 ft^3. To find the amount of gas to inject he
multiplied 90 x .0015 = .135 ft^3.
For each one hundred ft^3 of space
about .15 ft^3 of gas is required.


1 lb. CO 2 = 8.7 cubic feet


Small unventilated closet areas are
sometimes set up with a constant flow of
CO 2 enrichment when the lights are on.


Well designed ventilated rooms are re-
enriched every time the ventilation stops.
Unventilated rooms need a full
replenishment of CO 2 every one to two


hours.
A room 6 x 3 x 9 = 162 ft^3. The lights
are on continuously and the air is enriched
with a steady flow of.25 ft^3 of CO 2 per hour.


Six feet of gas is used per day. A 20 lb.
tank holds 20 x 8.7 = 174 ft^3 ÷ 6 = 29 days
of use per refill.
Growers often ventilate the hot air out
of the space to disperse heat. They found
that it does not do much for the plants to
run the CO 2 enrichment system and the


ventilation system at the same time, since
the gas is drawn out. Instead, the CO 2 unit


goes on after the ventilation system has

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