1088 26 Equilibrium Statistical Mechanics. II. Statistical Thermodynamics
EXAMPLE26.2
Show that ln(N−1) differs from ln(N) by a term that is proportional to 1/N.
Solution
ln(N−1)ln(N)+ln
(
1 −
1
N
)
The Taylor series that represents ln(1−x)is
ln(1−x)ln(1)+
1
1!
(
dln(1−x)
dx
)
x 0
x+O(x^2 )
0 −x+O(x^2 )
whereO(x^2 ) stands for terms that have powers ofxat least as great asx^2.
ln(N−1)ln(N)−
1
N
Exercise 26.4
Equation (26.1-27) can also be obtained by pretending thatNcan take on any real value and
performing the differentiation in Eq. (26.1-23). Carry out this differentiation.
The Gibbs Energy of a Dilute Gas
The Gibbs energy is defined by
GA+PV (26.1-28)
so that
G−NkBTln
(z
N
)
−NkBT+NkBT
G−NkBTln
(z
N
)
(26.1-29)
Note that
GNμ (26.1-30)
This is a version of Euler’s theorem, which is discussed in Part I of this textbook.
PROBLEMS
Section 26.1: The Statistical Thermodynamics of a
Dilute Gas
26.1 Consider the two isotopic substances^17 O 2 and^16 O^18 O.
Round off the atomic masses in amu to the nearest integer.
Answer the following questions without detailed
calculation:
a.How will the translational partition functions of the two
molecules compare at equal volumes and equal
temperatures?