Irodov – Problems in General Physics
3.169. (a) 11 1 = 23-ca/S 2 ; (b) E 231a//S 2. 3.170. t = -RC In (I - VIVO = 0.6 tis. 3.171. p = %leo In 2 = 1.4.10 13 5 - 2•m. ...
3.205. (a) I = (V 0IR) e-2tIRC- ' (b) Q = 1 /4 3.206. elm = lcor/qR = 1.8.10 11 C/kg. 3.207. p = lImle = 0.40 RN • s. 3.208. s = ...
3.236. B = Ron//1/1 (2R//) 2. 3.237. (a) B 1 / 2 p,^0 n1 (1 — x/V x 2 + R 2 ), where x> 0 outside the solenoid and x < 0 i ...
0 2 - 3.264. him = V 2F11in/RonR. 3.265. P = v 2 B 2 d 2 RI(R pd/S) 2 ; when R = pd/S, the power is P = P max = 1 14v 2 B 2 dS1p ...
Fig. 25. 3.292. g = 1/i 2 (-1)- Bafit, where n = 1, 2,... is the num- ber of the half-revolution that the loop performs at the g ...
3.318. /iDpm ' o = 0.7 ms, where p is the resistivity, po is the density of copper. 3.319. Li — 1/ 2 :: In = 0.26 p,H/m. 1 3.320 ...
3.351. fd-={ 1 / 2 :Eir for r < R, 112 BR^2 Ir for r > R. Here h = p,on/mo) 2 sin cot. 3.352. (a) jd = 42 itrvq 3 ; (b) jd ...
3.368. (a) E' = 13B — 1.4 nV/m; cv'1—R2 (b) B' =B 1-132 co t32 s2 a 0.9 T, 51°. 3.370. B' B 1 — (E I cB) ^.e^2 ., 0.15 mT. 3.371 ...
3.380. (a) p=qrB; T =m^0 c^2 (1/ 1+ (qrBlm- oc)^2 —1); (c) w = C^2 (1) (^) mv leB 3.384. r 2p I sin (cp/2) I , where p —m eB (^) ...
3.397. (a) T = (e 7E2Vm 2 r B)2 =--- 12 MeV; (b) T v MHz. r 2 3.398. (a) t= meV = 17 ps; 17 (b) s^ 4a9v2mr2 3eV 0.74 km. N Instr ...
4.4. co= li(/4— v:)/(x^22 — 4), a (/4 — v.^2 x^2 2 )/(vf i. —74). 4.5. (a) (v) = 3a1 T = 0.50 m/s; (b) (v) = 6a1 T = 1.0 m/s. g ...
4.18. T =n1/ mlIF = 0.2 s. 4.19. T =2:t y (1-1)=1.1 s. 4.20. T = 2 1/ llg[3112+arcsin(a/13)]. 17 2 — where = 4.21. t u' h 1— 1/- ...
Integrating these equations, with the initial conditions taken into account, we get x =--- (volco) (1 — cos cot), y = (vo/o)) si ...
x° 4.69. (a) ao — , a = — n/2, when xo > (b) ao = TE/2, when xo <0; = I xo^ ±(13/co)^2 , a = arctan (-13/4 with —3-[/2 < ...
4.90. (a) Q 1 / 2 17 (0 40782 )a S tan2 1 — 2.2; (b) A = nma 2 (4- (0 2 ) tan q ------ 6 mJ. Here coo = V x/m. 4.91. (a) (1))- ...
4.112. Q= (^17 ) 17 -^16 = = 1 .0 10^2. 4.113. (P) =R (I 2 ) 112 RA = 20 mW. 4.114. (P) = 1 i 2 RCV,%/L = 5 mW. 4.115. w= /- V L ...
4.133. / 0 // = -V1 (Q 2 + 1/ 4 ) (1 2 — 1) 2 /1^2 , 2.2 and 19 respectively. 4.134. t = i/zato. 4.135. (a) I = —Io z 1.154; (b) ...
/ / , / / / / /^ / / 11./2 (6) g A 2/2 / / / / / / / , Am./ 4.156. See Fig. 33. 4.157. AT = — In (1 — r1) =0.3 rad. 4.158. r = ( ...
4.164. Fee Fig. 35, for (a) and (b); see Fig. 36 for (c). 4.165. (a) ivp =^1 /^2 pa^2 w^2 sin^2 kx•cos^2 wt;^ (b) wk =^1 /^2 pa^ ...
4.175. u=_- vvo(V1 + (v/v 0 ) 2 —1) (^) 2vvvo = 0.5 m/s. 4.176. 0.) = aAv (1/1 + (Av/v 0 ) 2 — 1) = 34 s- 1. 4.177. v= vo /V1 + ...
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