Schaum's Outline of Discrete Mathematics, Third Edition (Schaum's Outlines)

(Martin Jones) #1

CHAP. 1] SET THEORY 15


1.13 Determine the validity of the following argument:
S 1 : All my friends are musicians.
S 2 : John is my friend.
S 3 : None of my neighbors are musicians.

S: John is not my neighbor.
The premisesS 1 andS 3 lead to the Venn diagram in Fig. 1-8(a).ByS 2 , John belongs to the set of friends which is
disjoint from the set of neighbors. ThusSis a valid conclusion and so the argument is valid.

Fig. 1-8

FINITE SETS AND THE COUNTING PRINCIPLE


1.14 Each student in LiberalArts at some college has a mathematics requirementAand a science requirementB.
A poll of 140 sophomore students shows that:
60 completedA, 45 completedB, 20 completed bothAandB.
Use a Venn diagram to find the number of students who have completed:
(a) At least one ofAandB; (b) exactly one ofAorB; (c) neitherAnorB.
Translating the above data into set notation yields:
n(A)=60,n(B)=45,n(A∩B)=20,n(U)= 140
Draw a Venn diagram of setsAandBas in Fig. 1-1(c). Then, as in Fig. 1-8(b), assign numbers to the four regions as
follows:
20 completed bothAandB,son(A∩B)=20.
60 − 20 =40 completedAbut notB,son(A\B)=40.
45 − 20 =25 completedBbut notA,son(B\A)=25.
140 − 20 − 40 − 25 =55 completed neitherAnorB.
By the Venn diagram:

(a)20+ 40 + 25 =85 completedAorB. Alternately, by the Inclusion–Exclusion Principle:
n(A∪B)=n(A)+n(B)−n(A∩B)= 60 + 45 − 20 = 85
(b)40+ 25 = 65 completed exactly one requirement. That is,n(A⊕B)=65.
(c) 55 completed neither requirement, i.e.n(AC∩BC)=n[(A∪B)C]= 140 − 85 =55.

1.15 In a survey of 120 people, it was found that:
65 readNewsweekmagazine, 20 read bothNewsweekandTime,
45 readTime, 25 read bothNewsweekandFortune,
42 readFortune, 15 read bothTimeandFortune,
8 read all three magazines.
Free download pdf