Cambridge International Mathematics

ANSWERS 741

8

We notice that:

²cos(x¡ 90 o) = sinxfas graphs coincideg

²y= cosx¡ 2 isy= cosxtranslated

¡ 0

¡ 2

¢

EXERCISE 29H

1a

b

c

d

e

f

g

h

2a

b

c

d

e

f

1

-1

-2

-3

x

y

yx¡=¡cos¡

90°90° 180°180° 270°270° 360°360°

yx¡=¡sin¡

yx¡=¡cos()¡-¡90°

yx¡=¡cos¡ ¡-¡2

O

3

2

1

-1

-2

-3

x

y

O 180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡2

yx¡=¡sin¡

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡

O

yx¡=¡2sin¡ ¡

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

O

yx¡=¡sin¡

yx¡=¡-sin¡

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡

O

yx¡=¡sin(\Qw_\ )

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡

O

yx¡=¡3sin¡

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡

O

yx¡=¡3sin(\Qw_\ )

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡

O

yx¡=¡2sin() 3

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡sin¡

O

yx¡=¡-sin() 2

3

2

1

-1

-2

-3

x

y

O 180°180° 360°360° 540°540° 720°720°

yx¡=¡cos¡

yx¡=¡2cos¡

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡cos¡

O

yx¡=¡cos(\Qw_\ )

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡cos¡

O

yx¡=¡-cos¡

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡cos¡

O

yx¡=¡3cos() 2

3

2

1

-1

-2

-3

x

y

180°180° 360°360° 540°540° 720°720°

yx¡=¡cos¡

O

yx¡=¡-2cos¡

3

2

1

-1

-2

-3

x

y

180°180°

360°360°

540°540°

720°720°

yx¡=¡cos¡

O

yx¡=¡\Qw_\(cos¡3)

IB MYP_3 ANS

cyan magenta yellow black

(^05255075950525507595)
100 100
(^05255075950525507595)
100 100
Y:\HAESE\IGCSE01\IG01_an\741IB_IGC1_an.CDR Friday, 21 November 2008 9:20:36 AM PETER