The Chemistry Maths Book, Second Edition

(Grace) #1

124 Chapter 4Differentiation



  1. 58.p(V 1 − 1 nb) 1 − 1 nRT 1 = 10 59.


Differentiate


60.sin


− 1

12 x 61.tan


− 1

1 x


2


  1. 63.sinh


− 1

12 x 64.tanh


− 1

1 x


2

Section 4.7


Find


65.x


2

1 + 1 y


2

1 = 14 66.y


3

1 + 13 x 1 + 1 x


2

1 − 111 = 10 67.x 1 = 1 y 1 ln 1 xy






Section 4.8


Differentiate:





    1. 71.sin




122

1 x 1 cos


3

(x


2

1 + 1 1)tan


123

12 x


72.Show that the equations


are equivalent expressions of the Clausius–Clapeyron equation.


73.The decomposition of dinitrogen pentoxide in tetrachloromethane atT 1 = 1 45°Chas


stoichiometry:


and obeys first-order kinetics. From the volumes of oxygen liberated after various times t,


the following concentrations of N


2

O


5

were obtained:


x 1 = 1 [N


2

O


5

] 2 mol 1 dm


− 3

2.33 1.91 1.36 1.11 0.72 0.55


t 2 s 0.0 319 867 1196 1877 2315


Plot a graph of ln xagainstt 2 sand determine the rate constant.


Section 4.9


74.Find all the nonzero derivatives of the functiony 1 = 13 x


5

1 + 14 x


4

1 − 13 x


3

1 + 1 x


2

1 − 12 x 1 + 11.


75.Find for the functiony 1 = 1 ln x.


76.Find a general formula for the nth derivative ofe


3 x

.


77.Find a general formula for the nth derivative of cos 12 x.


Section 4.10


Find the maximum and minimum values and the points of inflection of the following


functions. In each case, sketch the graph and show the positions of these points.


78.y 1 = 1 x


2

1 − 13 x 1 + 12 79.y 1 = 1 x


3

1 − 17 x


2

1 + 115 x 1 − 19 80.y 1 = 14 x


3

1 + 16 x


2

1 + 13


81.y 1 = 1 xe


−x

(see Figure 3.20)


dy


dx


dy


dx


dy


dx


dy


dx


,,,


2

2

3

3

4

4

NO NO O


25 2

1

2 2

→+ 2


dp


dT


H


RT


dp


dT


pH


RT


ln


=



=



vap vap

and


22

()()


()( )


11


213 21


212

213

+−


++−


xx


xxx


3


4


13












x


x


y


y


xy x


222

2


+− + += 320


dy


dx


:


cos














1

1


1


x


x


p


na


V



  • Vnb nRT










−=


2

2

pV nRT ()


nB


V


=+







1 

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