The Chemistry Maths Book, Second Edition

(Grace) #1

258 Chapter 9Functions of several variables


subject to the constraint


where theC


ij

are constants (withC


ij

1 = 1 C


ji

). For example, forn 1 = 13 ,


f(x


1

, x


2

, x


3

) 1 = 1 C


11

x


1

2

1 + 12 C


12

x


1

x


2

1 + 12 C


13

x


1

x


3

1 + 1 C


22

x


2

2

1 + 12 C


23

x


2

x


3

1 + 1 C


33

x


3

2

with constraintg 1 = 1 x


1

2

1 + 1 x


2

2

1 + 1 x


3

2

1 = 11.


By the method of Lagrange multipliers the stationary values of the function are


obtained by forming the auxiliary functionφ 1 = 1 f 1 − 1 λgand solving equations (9.14).


For the casen 1 = 13 , we have


φ 1 = 1 (C


11

1 − 1 λ)x


1

2

1 + 12 C


12

x


1

x


2

1 + 12 C


13

x


1

x


3

1 + 1 (C


221

− 1 λ)x


2

2

1 + 12 C


23

x


2

x


3

1 + 1 (C


33

1 − 1 λ)x


3

2

Differentiation with respect to x


1

,x


2

, and x


3

and setting each derivative to zero then


gives the set of simultaneous equations


(C


11

1 − 1 λ)x


11


  • 1 C


12

x


2


  • 1 C


13

x


3

1 = 10


C


21

x


1

1 + 1 (C


221

− 1 λ)x


2

1 + 1 C


23

x


3

1 = 10


C


31

x


11


  • 1 C


32

x


21


  • 1 (C


33

1 − 1 λ)x


3

1 = 10


Equations of this kind are often called secular equations. They occur, for example, in


the ‘method of linear combinations’ in quantum chemistry, when the quadratic form


represents the energy of the system (or an orbital energy in molecular orbital theory)


and the numbersx


1

, x


2

,1=, x


n

provide a representation of the state (of an orbital in


molecular orbital theory). The significance and solution of such systems of equations


are discussed in Chapters 17 and 19.


0 Exercise 30


9.5 The total differential


Letz 1 = 1 f(x, y)be a function of the variables xand y, and let the values of the variables


change continuously from(x, y), at point p in Figure 9.5, to(x 1 + 1 ∆x, y 1 + 1 ∆y)at point


q. The corresponding change in the function is


∆z 1 = 1 z


q 1

− 1 z


p 1

= 1 f(x 1 + 1 ∆x,y 1 + 1 ∆y) 1 − 1 f(x,y)


and is shown in the figure as the displacement P to Q on the representative surface of


the function; ∆zis the change of ‘height’ on the surface.


gx x ...x x


n

i

n

i

()


12

1

2

,,, = = 1


=

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