13.5 The Hermite equation 381
The integrand is an even function of xin the interval− 11 ≤ 1 x 1 ≤ 11. Therefore
(Section 5.3, equation (5.25))
(ii)P
22(x) 1 = 1 3(1 1 − 1 x
2), P
32(x) 1 = 115 x(1 1 − 1 x
2)
The integrand is an odd function of xin the interval − 11 ≤ 1 x 1 ≤ 11 , and I 1 = 10
(Section 5.3, equation (5.26))
0 Exercise 20
13.5 The Hermite equation
The Hermite equation is
y′′ 1 − 12 xy′ 1 + 12 ny 1 = 10 (13.30)
where nis a real number. The equation arises in the solution of the Schrödinger
equation for the harmonic oscillator. It is solved by the power-series method to give a
general solution
y(x) 1 = 1 a
0y
1(x) 1 + 1 a
1y
2(x)
in which the particular solutiony
1contains only even powers of xandy
2only odd
powers of x. As in the case of the Legendre equation,y
1reduces to a polynomial of
degree nwhen (positive) nis an even integer, and similarly fory
2when nis an odd
integer. These polynomials are called Hermite polynomialsH
n(x), and they are those
solutions of the Hermite equation that are of interest in the physical sciences:
(13.31)
forn 1 = 1 0, 1, 2, 3, =The first few of these polynomials are
H
0(x) 1 = 11 H
1(x) 1 = 12 x
H
2(x) 1 = 14 x
21 − 12 H
3(x) 1 = 18 x
31 − 112 x (13.32)
Hx x
nn
x
nn n n
nnn() ( )
()
()
()( )(
=−
−
!
−− −
−2
1
1
2
123
2))
()
2
2
4!
−
−x
nIPxPxdx xxdx==−
−+−+ZZ
1122321122() () 45 ( ) 1
=−+ −
32 0=
5301xxx
I=− −=−+−xxdx xxdx
++31 51 3 561
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