The Chemistry Maths Book, Second Edition

(Grace) #1

2.4 Inverse functions 37


both numerator and denominator have the common factor x, and can be divided by


this factor (whenx 1 ≠ 10 ) without changing the value of the fraction:


EXAMPLE 2.7Simplification of fractions


(1)


(2)


(3)


0 Exercises 17–22


2.4 Inverse functions


Given some functionfand the equationy 1 = 1 f(x), it is usually possible to define, at least


for some values of xand y, a function gsuch thatx 1 = 1 g(y). This new function is the


inverse functionoffand is denoted by the symbolf


− 1

(not to be confused with the


reciprocal 12 f):


ify 1 = 1 f(x)thenx 1 = 1 f


− 1

(y) (2.7)


EXAMPLE 2.8Ify 1 = 1 f(x) 1 = 12 x 1 + 1 3, findx 1 = 1 f


− 1

(y).


To find xin terms of y,


(i) subtract 3 from both sides of the equation: y 1 = 12 x 1 + 131 → 1 y 1 − 131 = 12 x


(ii) divide both sides by 2:


Thereforex 1 = 1 (y 1 − 1 3) 221 = 1 f


− 1

(y).


In this example, yis a single-valuedfunction of x; that is, for each value of xthere


exists just one value of y. Similarly, xis a single-valued function of y.


0 Exercises 23–25


EXAMPLE 2.9If , express xin terms of y.
y


ax b


cx d


=












=


y


x


3


2


ab


aabb


abab


abab


ab


a


22

22

2



++


=


+−


++


=



()()


()()


()


( ++b)


36


918


31 2


312


12


31 2


2









=










=










y


x


y


x


y


x


()


()


()


4


2


22


2


x 2


y


x


y


x


y


=


×


×


=


()


()


xy x


xxy


xy x


xy


yx


y










=










=










2


46


2


223


2


22 3


2

()


()()

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