374 IX The Number of Prime Numbers
is defined forRs>h, where h> 0. If there exists a constant A and a function G(s),
which is continuous in the closed half-planeRs≥h, such that
G(s)=F(s)−Ah/(s−h) forRs>h,
then
φ(x)∼Aehx for x→+∞.
Proof For eachX>0wehave
∫ X
0
e−sxdφ(x)=e−sX{φ(X)−φ( 0 )}+s
∫ X
0
e−sx{φ(x)−φ( 0 )}dx.
For reals=ρ>hboth terms on the right are nonnegative and the integral on the left
has a finite limit asX→∞. Hencee−ρXφ(X)is a bounded function ofXfor each
ρ>h. It follows that ifRs>hwe can letX→∞in the last displayed equation,
obtaining
F(s)=s
∫∞
0
e−sx{φ(x)−φ( 0 )}dx forRs>h.
Hence
[G(s)−A]/s=F(s)/s−A/(s−h)=
∫∞
0
e−(s−h)x{α(x)−A}dx,
whereα(x)=e−hx{φ(x)−φ( 0 )}. Thus we will prove the theorem if we prove the
following statement:
Letα(x)be a nonnegative function for x≥ 0 such that
g(s)=
∫∞
0
e−sx{α(x)−A}dx,
where s=σ+i t , is defined for everyσ> 0 and the limit
γ(t)= lim
σ→+ 0
g(s)
exists uniformly on any finite interval−T≤t≤T. If, for some h> 0 ,ehxα(x)is a
nondecreasing function, then
lim
x→∞
α(x)=A.
In the proof of this statement we will use the fact that the Fourier transform
kˆ(u)=
∫∞
−∞
eiutk(t)dt