444 DIFFERENTIAL EQUATIONSNow try the following exercise.Exercise 177 Further problems on families
of curves- Sketch a family of curves represented by each
of the following differential equations:
(a)dy
dx=6 (b)dy
dx= 3 x(c)dy
dx=x+ 2- Sketch the family of curves given by the equa-
tiondy
dx= 2 x+3 and determine the equation
of one of these curves which passes through
the point (1, 3). [y=x^2 + 3 x−1]46.2 Differential equations
Adifferential equationis one that contains differ-
ential coefficients.
Examples include(i)dy
dx= 7 x and (ii)d^2 y
dx^2+ 5dy
dx+ 2 y= 0Differential equations are classified according to the
highest derivative which occurs in them. Thus exam-
ple (i) above is afirst order differential equation,
and example (ii) is asecond order differential
equation.
Thedegreeof a differential equation is that of the
highest power of the highest differential which the
equation contains after simplification.Thus(
d^2 x
dt^2) 3
+ 2(
dx
dt) 5
=7 is a second orderdifferential equation of degree three.
Starting with a differential equation it is possible,
by integration and by being given sufficient data to
determine unknown constants, to obtain the origi-
nal function. This process is called‘solving the
differential equation’. A solution to a differential
equation which contains one or more arbitrary con-
stants of integration is called thegeneral solution
of the differential equation.
When additional information is given so that con-
stants may be calculated theparticular solutionof
the differential equation is obtained. The additional
information is calledboundary conditions.Itwasshown in Section 46.1 thaty= 3 x+cis the generalsolution of the differential equationdy
dx= 3.Given the boundary conditionsx=1 andy=2,
produces the particular solution ofy= 3 x−1.
Equations which can be written in the form
dy
dx=f(x),dy
dx=f(y) anddy
dx=f(x)·f(y)can all be solved by integration. In each case it is
possible to separate they’s to one side of the equa-
tion and thex’s to the other. Solving such equations
is therefore known as solution byseparation of
variables.46.3 The solution of equations of the
form
dy
dx
=f(x)
A differential equation of the formdy
dx= f(x)is
solved by direct integration,i.e. y=∫
f(x)dxProblem 2. Determine the general solution ofxdy
dx= 2 − 4 x^3Rearrangingxdy
dx= 2 − 4 x^3 gives:dy
dx=2 − 4 x^3
x=2
x−4 x^3
x=2
x− 4 x^2Integrating both sides gives:y=∫ (
2
x− 4 x^2)
dxi.e. y=2lnx−4
3x^3 +c,
which is the general solution.Problem 3. Find the particular solution of thedifferential equation 5dy
dx+ 2 x=3, given theboundary conditionsy= 12
5whenx= 2.