698 FOURIER SERIES
Now try the following exercise.
Exercise 249 Further problems on symme-
try relationships
- Determine the exponential form of the
Fourier series for the periodic function
defined by:
f(x)=
⎧
⎪⎪
⎪⎪
⎪⎪
⎨
⎪⎪
⎪⎪
⎪⎪
⎩
−2, when−π≤x≤−
π
2
2, when−
π
2
≤x≤+
π
2
−2, when+
π
2
≤x≤+π
and has a period of 2π
[
f(x)=
∑∞
n=−∞
(
4
nπ
sin
nπ
2
)
ejnx
]
- Show that the exponential form of the Fourier
series in problem 1 above is equivalent to:
f(x)=
8
π
(
cosx−
1
3
cos 3x+
1
5
cos5x
−
1
7
cos 7x+···
)
- Determine the complex Fourier series to rep-
resent the functionf(t)= 2 tin the range−π
to+π.
[
f(t)=
∑∞
n=−∞
(
j 2
n
cosnπ
)
ejnt
]
f(t)
20
− 1 01 t
L = 10
Figure 74.5
- Show that the complex Fourier series in
problem 3 above is equivalent to:
f(t)= 4
(
sint−
1
2
sin 2t+
1
3
sin 3t
−
1
4
sin 4t+···
)
74.5 The frequency spectrum
In the Fourier analysis of periodic waveforms seen
in previous chapters, although waveforms physically
exist in the time domain, they can be regarded as
comprising components with a variety of frequen-
cies. The amplitude and phase of these components
are obtained from the Fourier coefficientsanandbn;
this is known as afrequency domain. Plots of ampli-
tude/frequency and phase/frequency are together
known as thespectrumof a waveform. A simple
example is demonstrated in Problem 6 following.
Problem 6. A pulse of height 20 and width 2
has a period of 10. Sketch the spectrum of the
waveform.
The pulse is shown in Figure 74.5.
The complex coefficient is given by equation (12):
cn=
1
L
∫L
2
−L 2
f(t)e−j
2 πnt
L dt
=
1
10
∫ 1
− 1
20e−j
2 πnt
(^10) dt=
20
10
[
e−j
πnt
5
−jπn
5
] 1
− 1