Begin2.DVI

(Ben Green) #1
2. If f(t)is continuous and ta< tc< tb, then

∫tb

ta

f(t)dt =

∫tc

ta

f(t)dt +

∫tb

tc

f(t)dt

3. The modulus of the integral is less than or equal to the integral of the modulus

∣∣
∣∣

∫tb

ta

f(t)dt

∣∣
∣∣≤

∫tb

ta

|f(t)|dt

4. If F=F(t)is such that dF

dt

=F′(t) = f(t)for ta≤t≤tb, then

∫tb

ta

f(t)dt =F(t)]ttab=F(tb)−F(ta)

5. If G(t)is defined G(t) =

∫t

ta

f(t)dt, then dG

dt

=G′(t) = f(t)

6. The conjugate of the integral is equal to the integral of the conjugate

∫ tb

ta

f(t)dt =

∫tb

ta

f(t)dt

7. Let f(t, τ )denote a function of the two variables tand τwhich is defined and con-

tinuous everywhere over the rectangular region R={(t, τ )|ta≤t≤tb, τc≤τ≤τd}.

If g(τ) =

∫tb

ta

f(t, τ )dt and the partial derivatives of fexist and are continuous on

R, then

dg

=

∫tb

ta

∂f (t, τ )
∂τ

dt

which shows that differentiation under the integral sign is permissible.

Assume F(z) is an analytic function with derivative f(z) = dFdz and z=z(t) for

t 1 ≤t≤t 2 is a piecewise smooth arc C in a region Rof the z-plane, then one can

write ∫

C

f(z)dz =

∫t 1

t 1

dF
dz dz =F(z(t))

t 2
t 1

=F(z(t 2 )) −F(z(t 1 ))

This is a fundamental integration property in the z-plane. Note that if F(z) = U+iV

is analytic and f(z) = u+iv , then one can write

F′(z) = ∂U
∂x

+i∂V
∂x

=u+iv =∂V
∂y

−i∂U
∂y
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