remaining part of the energy released shows up as the kinetic energy of the
exhaust gases relative to a fixed point on the ground and as an increase in
the enthalpy of the gases leaving the engine.
Chapter 9 | 523EXAMPLE 9–9 The Ideal Jet-Propulsion CycleA turbojet aircraft flies with a velocity of 850 ft/s at an altitude where the air is
at 5 psia and 40°F. The compressor has a pressure ratio of 10, and the tem-
perature of the gases at the turbine inlet is 2000°F. Air enters the compressor
at a rate of 100 lbm/s. Utilizing the cold-air-standard assumptions, determine
(a) the temperature and pressure of the gases at the turbine exit, (b) the veloc-
ity of the gases at the nozzle exit, and (c) the propulsive efficiency of the cycle.Solution The operating conditions of a turbojet aircraft are specified. The
temperature and pressure at the turbine exit, the velocity of gases at the
nozzle exit, and the propulsive efficiency are to be determined.
Assumptions 1 Steady operating conditions exist. 2 The cold-air-standard
assumptions are applicable and thus air can be assumed to have constant
specific heats at room temperature (cp0.240 Btu/lbm · °F and k1.4).
3 Kinetic and potential energies are negligible, except at the diffuser inlet
and the nozzle exit. 4 The turbine work output is equal to the compressor
work input.
Analysis The T-sdiagram of the ideal jet propulsion cycle described is shown
in Fig. 9–50. We note that the components involved in the jet-propulsion
cycle are steady-flow devices.
(a) Before we can determine the temperature and pressure at the turbine
exit, we need to find the temperatures and pressures at other states:
Process 1-2(isentropic compression of an ideal gas in a diffuser): For con-
venience, we can assume that the aircraft is stationary and the air is moving
toward the aircraft at a velocity of V 1 850 ft/s. Ideally, the air exits the
diffuser with a negligible velocity (V 2 0):Process 2-3(isentropic compression of an ideal gas in a compressor):T 3 T 2 aP 3
P 2b1 k 1 2>k
1 480 R 211021 1.4^1 2>1.4927 RP 3 1 rp 21 P 22 11021 8.0 psia 2 80 psia 1 P 42P 2 P 1 aT 2
T 1bk>1k 12
1 5 psia2a480 R
420 Rb1.4>11.4 12
8.0 psia480 R420 R1 850 ft>s 22
21 0.240 Btu>lbm#R 2a1 Btu>lbm
25,037 ft^2 >s^2bT 2 T 1 V^21
2 cp0 cp 1 T 2 T 12 V 12
2h 2 V 22
2h 1 V^21
2P = const.P = const.sT, °Fqinqout654322000–40 1FIGURE 9–50
T-sdiagram for the turbojet cycle
described in Example 9–9.0
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