FRICTION 177
Now try the following exercise
Exercise 76 Further problems on friction
on an inclined plane
Where necessary, takeg= 9 .81 m/s^2
- A mass of 40 kg rests on a flat horizon-
tal surface as shown in Figure 15.13. If
the coefficient of frictionμ= 0 .2, deter-
mine the minimum value of a horizontal
forcePwhich will just cause it to move.
[78.48 N]
Motion
mg
P
Figure 15.13
- If the mass of Problem 1 were equal to
50 kg, what will be the value ofP?
[98.1 N] - An experiment is required to obtain the
static value ofμ; this is achieved by
increasing the value ofθuntil the mass
just moves down the plane, as shown
in Figure 15.14. If the experimentally
obtained value forθ were 22.5°,what
is the value ofμ?[μ= 0 .414]
q
mg
N
Motion F
Figure 15.14
- If in Problem 3,μwere 0.6, what would
be the experimental value ofθ?
[θ= 30. 96 °]
5. For a mass of 50 kg just moving up an
inclined plane, as shown in Figure 15.5,
what would be the value ofP, given that
θ= 20 °andμ= 0 .4? [P= 352 .1N]
6. For a mass of 50 kg, just moving
down an inclined plane, as shown in
Figure 15.7, what would be the value of
P, given thatθ= 20 °andμ= 0 .4?
[P= 16 .6N]
7. If in Problem 5,θ = 10 °andμ= 0 .5,
what would be the value ofP?
[P= 326 .7N]
8. If in Problem 6,θ = 10 °andμ= 0 .5,
what would be the value ofP?
[P= 156 .3N]
9. Determine P for Problem 5, if it
were acting in the direction shown in
Figure 15.8. [P= 438 .6N] - Determine P for Problem 6, if it
were acting in the direction shown in
Figure 15.10. [P= 20 .69 N] - Determine the value forθwhich will just
cause motion down the plane, whenP=
250 N and acts in the direction shown in
Figure 15.12. It should be noted that in
this problem, motion is down the plane.
[θ= 19. 85 °] - If in Problem 11,θ= 30 °, determine the
value ofμ.[μ= 0 .052]
15.8 The efficiency of a screw jack
Screw jacks (see Section 18.4, page 202) are often
used to lift weights; one of their most common uses
are to raise cars, so that their wheels can be changed.
The theory described in Section 15.7 can be used to
analyse screw jacks.
Consider the thread of the square-threaded screw
jack shown in Figure 15.15.
Letpbe the pitch of the thread, i.e. the axial
distance that the weightWis lifted or lowered when
the screw is turned through one complete revolution.
From Figure 15.15, the motion of the screw in lifting
the weight can be regarded as pulling the weight by
a horizontal forceP,upaninclineθ,where
tanθ=
p
πd
,