82 MECHANICAL ENGINEERING PRINCIPLESAnswers to Exercise 31 (page 77)
A0000CD2 kN2 kN−3 kN −3 kN1 kN3 kNBBMDSFD
(c)C0000AD−2 kN m+2.5 kN−1.5 kN −1.5 kN−1 kN+3 kN mBBMDSFD
(d)SFD
(f)A0000CB−4 kN −4 kN−10 kN −10 kN−8 kN m−28 kN mBMDACBMDB
1m1.5 kN001.5 kN1.5 kN m−1.5 kN −1.5 kN1m00SFD
(a)ACBMDB
2m1.33 kN001.33 kN2.67 kN m−2.67 kN −2.67 kN1mSFD
(b)SFD
(g)A0000CB−2 kN −2 kN−3 kN m3 kN mBMDACDB00000.667 kN m−3.333 kN −3.333 kN3.333 kN mBMDSFD
(e)0.667 kN−2.667 kN mFigure 6.43