Cliffs AP Chemistry, 3rd Edition

. . mL NaClO mL NaClO mL Na S O mL Na S O 1 30 4 #^1 22 3= 75 22 3 would be needed for equivalency, but 20. mL of Na 2 S 2 O 3 w ...

Experiment 10 A: Determination of the Equilibrium Constant, Ka, for a Chemical Reaction Background: Weak acids, upon dissolving ...

solutions were labeled X, Y and Z respectively. Each of the solutions were diluted to a total volume of 100.00 mL with distilled ...

Z: HA volume sol n' 6@=initialmoles HA-molesOHadded (^332) . HA ... 0 10000L M 6@=5 00 10##---2 63 10 =237 10# - moles A–forme ...

Experiment 10 B: Determination of the Equilibrium Constant, Ksp, for a Chemical Reaction Background: Lead iodide is relatively i ...

Scenario:A student mixed 5.0 mL of 0.015 M Pb(NO 3 ) 2 with 3.0 mL of 0.030 M KI in 2.0 mL of 0.200 M KNO 3. The test tube was s ...

What was the molar concentration of Pb2+in the solution at equilibrium? 3 . .. L mol Pb M 0 010 37 10# -^52 =37 10# - Deter ...

Experiment 10 C: Determination of the Equilibrium Constant, Kc, for a Chemical Reaction Background: Many reactions do not go to ...

How many moles of FeSCN2+were in the mixture at equilibrium? Total volume of sol’n = 5.0 mL + 5.0 mL = 10.0 mL + ' . .'. L sol ...

Experiment 11: Determination of Appropriate Indicators for Various Acid-Base Titrations and Experiment 19: Preparation and Prope ...

In hydrolysis, a salt reacts with water. The ions that hydrolyze do so because a weak acid or a weak base is formed. The process ...

The simplest quantitative method for determining pH is with the use of indicators. An indicator is a colored substance usually d ...

A solution from Part I was determined to have a pH of 1.00. Determine the pOH, the [H 3 O+] and the [OH–]. pOH = 14.00 −pH = 14 ...

Since, // Ac HAc nV nV ' ' Ac sol n = HAc sol n 7 6 A @ Then, 7AHK+ ==a:#:#nnHAcAc- 18 10. --^55 0 05000 0488.. --x mol HA ...

Calculate the theoretical pH of the distilled water and added HCl (beaker 3). ..^2 HLL (.. ). mol H 0 0250 L M 0 250 0 0250 0 0 ...

Experiment 12: Determination of the Rate of a Reaction and Its Order and an Actual Student Lab Write-Up* Background: Reaction ra ...

Therefore a rate law can be created: rate = k (acetone)x⋅(I 2 )y⋅(H+)z It is known that the amount of iodine does not affect the ...

Ratio of rate IV to rate I: . . . .. .(.) .(. ) rate I rate IV k k 020 020 42 10 42 10 10 0 80 0 0010 0 80 0 00050 x y z x y z 6 ...

The student used the ratios in Mixture I and ran the experiment at two different tempera- tures. Calculate the rate, the rate c ...

Part III: AP Chemistry Laboratory Experiments A Sample Lab Report* I. Title: Chemical Kinetics: An Iodine Clock Reaction II. Dat ...